[SOLVED] Comp 3350: HW # 10: Theme: Strings and Arrays

Description

1. [Case Table] Write a program that asks the user to enter a score. It then adds 1 to the score, creating a final score and prints the letter grade based on the final score (see table below).  The program should display your original score, final score as well as the letter grade. You should reference the section of the text that discusses Table Driven Selection. Use the following data as a guide for letter grade and score range association:

Please embed your code into your homework submission along with a screen shot post execution.

INCLUDE Irvine32.inc

.data

score BYTE “Enter your score (0 – 100): “, 0 msg1 BYTE “The original score is: “, 0 msg2 BYTE “The letter grade is: “, 0 out1 BYTE “A”, 0 out2 BYTE “B”, 0 out3 BYTE “C”, 0 out4 BYTE “D”, 0 out5 BYTE “F”, 0

.code main PROC mov edx, OFFSET score call WriteString call ReadDec mov edx, OFFSET out1 cmp eax, 89 jae LBX mov edx, OFFSET out2 cmp eax, 79 jae LBX mov edx, OFFSET out3 cmp eax, 69 jae LBX mov edx, OFFSET out4 cmp eax, 59 jae LBX mov edx, OFFSET out5 cmp eax, 0 jae LBX

LBX: push edx mov edx, OFFSET msg1 call WriteString

call WriteDec call Crlf pop edx push edx mov edx, OFFSET msg2 call WriteString pop edx call WriteString call Crlf exit main ENDP END main

2. [Strings] Write a program that copies bytes from source to target. You must use string instructions to accomplish the job. Declare the source and target locations in the data segment.  The source string should be your name.

INCLUDE Irvine32.inc

.data

str1 BYTE “Zejian Zhong”, 0 str2 BYTE 20 DUP(?)

msg1 BYTE “The source string is: “, 0 msg2 BYTE “The target string is: “, 0

.code main PROC mov edx, OFFSET msg1 call WriteString mov edx, OFFSET str1 call WriteString call Crlf mov edx, OFFSET msg2 call WriteString cld

mov ecx, LENGTHOF str1 mov esi, OFFSET str1 mov edi, OFFSET str2 rep movsb mov edx, OFFSET str2 call WriteString call Crlf     EXIT main ENDP END main

3. [General Programming] Write a program that converts the temperature in Celsius to F in Fahrenheit using F = C*9/5 + 32. For ease of programming you can display the result in fractions, i.e. 20 1/9 (no need to use floats, just display the quotient, the slash character and the digit 9).  Show the runs for freezing, boiling point, room temperature and human body temperature.   Provide screen shots of the runs along with your program.

INCLUDE Irvine32.inc

.data

cel BYTE “Celsius = “, 0 fah BYTE “Fahrenheit = “, 0 denominator BYTE “/5″, 0 space BYTE ” “, 0

.code main proc mov edx, OFFSET cel call WriteString call ReadInt push eax call converter call Crlf exit main ENDP  converter proc push ebp mov ebp, esp mov eax, [ebp+8] imul eax, 9 mov ebx, +5 cdq idiv ebx add eax, 32 push edx mov edx, OFFSET fah call WriteString pop edx call WriteInt push edx mov edx, OFFSET space call WriteString pop edx push eax mov eax, edx test eax,eax jns NonNeg theNeg: neg eax NonNeg: cmp eax, 0 je fract call WriteDec pop eax push edx mov edx, OFFSET denominator call WriteString pop edx jmp endexit fract: pop eax endexit: pop ebp ret 4 converter ENDP

END main

Freezing point = 0°C

Boiling point = 100°C

Room temperature = 24°C

Body temperature = 37°C

4. [Strings] Write a program that searches for a character in a string. You should set the EDI pointer to point to the character found. Test the program thoroughly using various strings, including your name.  Provide screen shots of the runs along with your program.  You must use string instructions in your program.

INCLUDE Irvine32.inc

.data                                                            My name

MAX = 100

str0 BYTE “The string is: “, 0 str1 BYTE MAX+1 DUP(?)

str2 BYTE “Trying to find character ‘i’.”, 0 found BYTE “Result: Found”, 0 notfound BYTE “Result: Not found”, 0

.code main PROC

push edx

mov edx, OFFSET str0

call WriteString     Apple  mov edx, OFFSET str1 mov ecx, MAX call ReadString mov edx, OFFSET str2 call WriteString call Crlf mov edi, OFFSET str1 mov al, ‘i’ mov ecx, LENGTHOF str1

cld     repne scasb

jnz cannotfound      ^Banana  dec edi mov edx, OFFSET found call WriteString call Crlf jmp quit  cannotfound:

mov edx, OFFSET notfound

call WriteString      call Crlf

iPhone X quit:         exit main ENDP END main