Description
Linear elastic isotropic material) Derive G = E / 2 (1+v) for linear elastic isotropic materials. E, G (or according to the Bower textbook), and v are Young’s modulus, shear modulus, and Poisson’s ratio, respectively.
- [30 points] (Constitutive relationship) Derive constitutive relationship under the plane strain and stress conditions (i.e., derive expressions in Sec. 3.2.3. in the Bower book from the full 3D expressions).
- [20 points] (Constitutive relationship) Given a state of strain at a point in an isotropic material,
| é 0.001 ê
e=ê 0.001 êë -0.002 |
0.001 0
0.005 |
-0.002 ùú
0.005 ú 0 úû |
Determine stress tensor. Assume E = 200 GPa and v = 0.3.
- [30 points] (Coordinate transformation) An equi-triangular strain rosette is mounted on the surface of a body as shown below.
The strain gauge readings are:
𝜀0° = 0.005, 𝜀60° = 0.002, 𝜀120° = −0.001
The material properties are E = 200 GPa and v = 0.3. Find the stress tensor along the xy axes at point O
